The first transfer dilutes the original solution by a factor of (2 mL)/(100 mL) = 1/50, and the second dilutes the new solution by (5 mL)/(100 mL) = 1/20. So the total dilution is by a factor of (1/50)(1/20) = 1/1000, so the original concentration was 0.000158*1000 = 0.158 M.
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